Question

An object is dropped from a building and strikes the ground with a speed of 44 m/s. How tall is the building? *

Answer 1

d = 98.67m

Step-by-step explanation:

equation:

vf^2 = vi^2 + 2ad

(44m/s)^2 = (0m/s)^2 + 2(9.81m/s^2)(d)

1936m^2/s^2 = 19.62m/s^2(d)

divide both sides by 19.62m/s^2

d = 98.67m approximately