Answer:
Part A)
For 10 boxes

For 40 boxes

For 25 boxes

Part B) The number of boxes must be greater than or equal to 191 for a profit of at least $700
Part C) 151 boxes are needed to break even
Explanation:
we know that
Profit, is equals to revenue minus costs of goods sold
we have

Part A) Find the profit for
1) 10 boxes
For x=10 boxes
substitute in the formula


The negative means that the revenue is less than the costs
2) 40 boxes
For x=40 boxes
substitute in the formula


The negative means that the revenue is less than the costs
3) 40 boxes
For x=25 boxes
substitute in the formula


The negative means that the revenue is less than the costs
Part B) How many boxes needed for a profit of at least $700?
For P=$700
substitute in the formula and solve for x




Round up

therefore
The number of boxes must be greater than or equal to 191 for a profit of at least $700
Part C) How many boxes needed to “break even”?
we know that
Break even is when the profit is equal to zero
For P=0



Round up
151 boxes are needed to break even