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What does it mean to solve a quadratic equation such as x^2+4x+3=0?

User ZRoss
by
5.3k points

2 Answers

4 votes

Answer:

You need to find x

Explanation:

Given equation : x^2 + 4x + 3 = 0

Factorize and it will be (x+1)(x+3)

So x = -1 and -3

User Misanthrop
by
5.7k points
5 votes

Answer:

The quadratic equation is solved .we get value of x=-3 and -1

Given data:


x^(2)+4 x+3=0

To Find:

Solve a quadratic equation:

Solution:

Step 1:

This equation is already in the form "(quadratic) equals (zero)”


x^(2)+4 x+3= (x + 3)(x + 1)

(x + 3)(x + 1) = 0

Step 2:

Now I can solve each factor by setting each one equal to zero and solving the resulting linear equations:

x + 3 = 0 or x + 1 = 0

x = –3 or x = – 1

Step 3:

These two values are the solution to the original quadratic equation. So my answer is:

x = –3, –1

Step 4:

Checking x = –3:

[–3]2 + 4[–3] + 3

9 – 12 + 3

=-3+3

=0

Step 5:

Result

Checking x = –1:

[–1]2 + 4[–1] + 3

1 – 4 + 3

-3 +3 =0

The value of x=-3 and -1

User Sunil Patil
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4.8k points