Answer:
The probability of rolling a number greater than 4 or less than 3 is
![(2)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jgft8n5xwx5uidfnxss9gbutm3s8nfmtko.png)
Solution:
In the given question there are two events as follows:
(a) Rolling a number greater than 4 i.e. A = {5,6}
(b) Rolling a number less than 3 i.e. B = {1,2}
Since a die has 6 numbers,
P(A) =
where P(A) is the probability of occurrence of event A and P(B) =
![(2)/(6)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/cqk04s64kx8ifc6ip8qp9r23u02zcttsvv.png)
Since, Event A and Event B has nothing in common therefore they are mutually exclusive events.
P(A∪B) = P(A) + P(B)
![=(2)/(6)+(2)/(6)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qvn1cw85pj76k281gzcn1kkzm1u251zjhd.png)
![=(4)/(6)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/w3reur0uhxu0r0nx6e00m4pt042flpvbbo.png)
![=(2)/(3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/l0jnhobrui3bx5wujzp656kt2nrithbdou.png)
Therefore the probability of getting a number greater than 4 or less than 3 is
![(2)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jgft8n5xwx5uidfnxss9gbutm3s8nfmtko.png)