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(geometry) please look at attached image and help me with this question!

(geometry) please look at attached image and help me with this question!-example-1
User Passy
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1 Answer

2 votes

Answer:

m∠AEC = 139°

Explanation:

To make the equations easier to write, let's say all measures are in degrees, and define ...

p = m∠AEB = 11x -12

q = m∠CED = m∠CEB = 4x +1

Then ...

p + 2q = 180

(11x -12) + 2(4x +1) = 180

19x -10 = 180 . . . . . . . . . . . . collect terms

19x = 190 . . . . . . . . add 10

x = 10 . . . . . . . . . . . divide by 19

p = 11x -12 = 110 -12 = 98

q = 40 +1 = 41

The angle of interest is ...

m∠AEC = p +q = 98 +41

m∠AEC = 139 . . . . degrees

User James Wierzba
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