Question

The ages of three friends are consecutive integers. The sum of their ages is 45

Answer 1

their ages are 14, 15, and 16. Is that what you were asking?

Explanation:

let x be the age of the smallest friend

x+(x+1)+(x+2)=45

3x+3=45

3x=42

x=14

Answer 2

45 = (x) + (x + 1) + (x + 2)

45 = 3x + 3

- 3

42 = 3x

/3

14 = x

45 = 14 + (14 + 1) + (14 + 2)

45 = 14 + 15 + 16

The ages of the 3 friends are 14, 15, and 16.