Question

The length of a rectangle is 2 inches less than 3 times the number of inches in its width. If the perimeter of the rectangle

is 28 inches, what is the width and length of the rectangle?
(Width
sin., Length
alin.)

Answer 1

The length of the rectangle is 10 inches and the width is 4 inches

Explanation:

Let

L -----> the length of rectangle in inches

W ----> the width of rectangle in inches

we know that

The perimeter of rectangle is

`P=2(L+W)`

we have

`P=28\ in`

so

`28=2(L+W)`

simplify

`14=(L+W)` ----> equation A

`L=3W-2` ----> equation B

Solve the system of equations by substitution

Substitute equation B in equation A and solve for W

`14=(3W-2+W)`

`14=(4W-2)`

`4W=14+2`

`4W=16`

`W=4\ in`

Find the value of L

`L=3W-2`

`L=3(4)-2=10\ in`

therefore

The length of the rectangle is 10 inches and the width is 4 inches