Question

A supplier has 74.75 stone of wheat that contains 3500.0 moles of water. The wheat is to be ground into flour and

used to completely fill 4 containers that are 246.2 quarts each.

(a) What is the moisture content of the flour on a wet basis and a dry basis?

(b) What will be the density of the flour in SI units?

Answer 1

a) moisture content of the flour on a wet basis = 13.272%

moisture content of the flour on a dry basis = 15.303%

b) Density = 509.368 Kg/m³

Step-by-step explanation:

Given:

Mass of wheat = 74.75 stone

1 stone = 6.35029 kg

thus,

Mass of wheat = 74.75 × 6.35029 kg = 474.68 kg

Water content = 3500.0 moles

Molar mass of water = 18 g/mol

Thus, mass of water = 3500 × 18 = 63000 grams = 63 kg

a) moisture content of the flour on a wet basis

=
`\frac{\textup{Mass of water}}{\textup{Total mass of the wheat }}*100\%`

=
`\frac{\textup{63}}{\textup{474.68}}*100\%`

= 13.272%

moisture content of the flour on a dry basis

=
`\frac{\textup{Mass of water}}{\textup{Dry mass of the wheat }}*100\%`

=
`\frac{\textup{63}}{\textup{474.68-63}}*100\%`

= 15.303%

b) Total volume of the flour = 4 × 246.2 quarts = 984.8 quarts

also,

1 quarts = 0.000946353 m³

thus,

984.8 quarts = 984.8 × 0.000946353 m³ = 0.9319 m³

Now,

Density =
`\frac{\textup{Mass}}{\textup{Volume}}`

or

Density =
`\frac{\textup{474.68}}{\textup{0.9319 }}`

or

Density = 509.368 Kg/m³