Answer:
Explanation:
The answer is C. I have never had to rearrange the terms when factoring by grouping, but here I had to in order to get it to work. Rearranging makes the polynomial become:
3yz² + 6y³ - 4y²z - 2z³
Grouping:
(3yz² + 6y³) - (4y²z - 2z³)
Factoring out a 3y from the first term and a 2z out of the second term gives us:
3y(z² + 2y²) - 2z(2y² + z²)
Because addition is commutative, the terms inside the parenthesis are the same. We can factor that out now, leaving in another set of parenthesis what is left:
(2y² + z²)(3y - 2z)
That is C.