Question

Given the equation square root of 8x plus 1 = 5, solve for x and identify if it is an extraneous solution. x = one fourth, solution is not extraneous x = one fourth, solution is extraneous x = 3, solution is not extraneous x = 3, solution is extraneous

Answer 1

X=3, the solution is not extraneous.

Explanation:

Took quiz and got it right.

Answer 2

x=3, solution is not extraneous

Explanation:

we have

`√(8x+1)=5`

Solve for x

squared both sides

`(√(8x+1))^2=5^2`

`8x+1=25\\8x=25-1\\8x=24\\x=3`

Verify

For x=3

`√(8(3)+1)=5`

`√(24+1)=5`

`√(25)=5`

`5=5` -----> is true

therefore

x=3, solution is not extraneous