Answer:
The product of
and
is

Solution:
Here we have to multiply two numbers that is
and
which are in mixed form. We first convert them in fraction form to get the final product.
The number
can be written in fraction form as
![([(5 * 3)+2])/(5)=(17)/(5)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/zm11rky9j8m67qg29mfjm4hnsoeq74m4qw.png)
The number
can be written in fraction form as
![([3 * 2)+1])/(3)=(7)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/f2xipo6cc4c2jfqpfwmstatpdv1mgmsjb9.png)
Therefore multiplying
we get ,

When we divide 119 by 15 we get 6 as quotient and 1 as remainder.
Therefore
can be written in mixed form as
