17.5k views
1 vote
If the det(M)≠0 then A. some values of X will have no values of A which satisfy the equation. B. some values of X will have more than one value of A which satisfy the equation. C. given any A there is one and only one X which will satisfy the equation. D. some values of A (such as A=0 ) will allow more than one X to satisfy the equation. E. given any X there is one and only one A which will satisfy the equation. F. some values of A will have no values of X which will satisfy the equation.

User Nfvp
by
7.2k points

1 Answer

3 votes

Answer:

C. given any A there is one and only one X which will satisfy the equation.

D. some values of A (such as A=0 ) will allow more than one X to satisfy the equation.

Explanation:

If the value of the determinant is not equal to zero then the number of the solution depends on the rank of the augmented matrix (M), the rank of matrix A and the number of unknowns. Thus, the number of solutions of the matrix can be infinitely many solutions, a single solution or no solution.

User CuriousMonkey
by
7.5k points