Question

We are planning a reception for our daughter. The hall that we are renting charges a $95 cleanup fee. In addition to the cleanup fee, they charge $25 per guest for food and drinks. If we have $2,100.00 available, what is the maximum number of guest we can invite without going over our budget?

Answer 1

After deducting the $95 cleanup fee from the $2,100 budget, $2,005 remain for guests. Dividing this amount by the $25 per guest cost yields a maximum of 80 guests that can be invited within the budget.

Step-by-step explanation:

To calculate the maximum number of guests that can be invited to the reception within the budget of $2,100, first deduct the fixed cleanup fee of $95 from the total budget. This leaves $2,100 - $95 = $2,005 for food and drinks. Given that food and drinks cost $25 per guest, you would divide the remaining amount by $25 per guest to find out the number of guests you can afford to invite.

The calculation will be as follows:

Subtract the cleanup fee: $2,100 - $95 = $2,005

Divide the remaining budget by the cost per guest: $2,005 ÷ $25 ≈ 80

Therefore, the maximum number of guests that can be invited without exceeding the budget is 80.

Answer 2

We can invite at most 80 people without going over our budget.

Step-by-step explanation:

The available budget is $ 2,100.

As a fixed amount we must pay $ 95 for the cleaning service. After making this payment we would be available $ 2,100 - $ 95 = $ 2,005 to cover the food and drink expenses of the guests. Since for each guest they charge us $ 25, we can invite a maximum of 80 guests ($ 2,005 / $ 25 = 80.2). Considering that we will invite 80 people, the total cost of the event will be $ 95 + 80. $ 25 = $ 2,095, that is, we will finally have $ 5 left over.