Question

Two people, one with mass m1 and the other with mass m2, stand on a stationary sled with mass M on a frozen lake. Assume that the ice is frictionless. a) The first person (with mass m1) jumps off the sled with a velocity −sxˆ relative to the (stationary) sled. What is his velocity? Use conservation of momentum to find the velocity of the sled (which is still carrying the second person).

Answer 1

`V=(m_1s)/(m_2+M)`

Step-by-step explanation:

As we know that if there is no any external force on the system then the linear momentum of system will remain conserve.

Linear momentum P= m .v

If F(net) = 0
`P_i=P_f`

Given that velocity of first person is s .

Form conservation of momentum

Let V is the final velocity

Initial momentum =
`m_1.s`

Final momentum =
`(m_2+M)V`

`m_1s=(m_2+M)V`

`V=(m_1s)/(m_2+M)`