Answer:
T = 288.15 K
Step-by-step explanation:
from gas law for dry air, the average surface temperature of dry air in the atmosphere can be computed as:
![\rho = (P)/(RT)](https://img.qammunity.org/2020/formulas/geography/college/y20nj3u0s4j2wa46rvlh02bt3h2ha7kre9.png)
where,
is density of dry air = 1.225 kg/m3,
P is standard air pressure) =101.325 kPa = 101325 Pa,
R is gas constant = 287.05 J / (kg.K)
substituting the values, we get
![1.225 = (101325)/((287.05) (T))](https://img.qammunity.org/2020/formulas/geography/college/eujgtns0wd36kbd3asw5qgkkun0y5mpsho.png)
solving for T we get
![T = (101325)/(( (287.05) (1.225) ))](https://img.qammunity.org/2020/formulas/geography/college/2h12dsiieuohqkg5cyi11k2do0rdy57znq.png)
T = 288.15 K