Answer:
x = 5 , y = 3
Explanation:
Solve the following system:
{3 x + 4 y = 27 | (equation 1)
5 x - 3 y = 16 | (equation 2)
Swap equation 1 with equation 2:
{5 x - 3 y = 16 | (equation 1)
3 x + 4 y = 27 | (equation 2)
Subtract 3/5 × (equation 1) from equation 2:
{5 x - 3 y = 16 | (equation 1)
0 x+(29 y)/5 = 87/5 | (equation 2)
Multiply equation 2 by 5/29:
{5 x - 3 y = 16 | (equation 1)
0 x+y = 3 | (equation 2)
Add 3 × (equation 2) to equation 1:
{5 x+0 y = 25 | (equation 1)
0 x+y = 3 | (equation 2)
Divide equation 1 by 5:
{x+0 y = 5 | (equation 1)
0 x+y = 3 | (equation 2)
Collect results:
Answer: {x = 5 , y = 3