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What is the equation of the center(-5,-9) and radius 6

User JoeZuntz
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1 Answer

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assuming is a circle of course


\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-5}{ h},\stackrel{-9}{ k})\qquad \qquad radius=\stackrel{6}{ r} \\\\[-0.35em] ~\dotfill\\[2em] [x-(-5)]^2+[y-(-9)]^2=6^2\implies (x+5)^2+(y+9)^2=36

User Rana Imtiaz
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