Question

004 (part 1 of 2) 10.0 points A bug completes one lap along the edge of a circular planter of radius 11.7 cm in 13.91 s. How fast was it traveling? 1. 10.8518 2. 7.53496 3. 12.0428 4. 6.06143 5. 13.9643 6. 8.63381 7. 7.9597 8. 5.28492 9. 13.1952 10. 7.74398 Answer in units of cm/s

Answer 1

8.5.28 492 cm/s

Step-by-step explanation:

We are given that a bug completes one lap along edge of circular planter.

Radius of circular planter=11.7 cm

Time taken by bug=13.91 s

We have to find speed of traveling of bug

We know that speed =
`(distance)/(time)`

Distance traveled by bug=
`2\pi r`

`\pi=3.14`

Distance traveled by bug=
`2* 3.14* 11.7`

Speed of bug=
`(2\cdot 3.14\cdot 11.7)/(13.91)=5.2822 cm/s`

Hence, option 8 is true.

Answer: 8.5.28 492 cm/s

Answer 2

Speed of bug will be 5.2822 cm /sec

Step-by-step explanation:

We have given radius of the circular planter = 11.7 cm

We know that circumference
`C=2\pi r=2* 3.14* 11.7=73.476m`

It is given that bug completes on lap in 13.91 sec

So time t = 13.91 sec

We have to find the speed that is how fast it was traveling

So speed
`v=(distance)/(time)=(73.476)/(13.91)=5.2822cm/sec`

So speed of bug will be 5.2822 cm /sec