Answer:
![\large\boxed{y=(2)/(3)x+1}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/f6tzet5exd0rqs1n8vjfpf06tn6b672h88.png)
Explanation:
The slope-intercept form of an equation of a line:
![y=mx+b](https://img.qammunity.org/2020/formulas/mathematics/high-school/8nudzfk4b5l0arb9iixag2w8am6zn99zlr.png)
m - slope
b - y-intercept → (0, b)
The fromual of a slope:
![m=(y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/fc06wy5n2hf2a0hmyba6df4ibmxk1cn53a.png)
(x₁, y₁), (x₂, y₂) - points on a line
We have the points from the graph:
(0, 1) → b = 1 and (3, 3).
Calculate the slope:
![m=(3-1)/(3-0)=(2)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/bt1okzik8a97p78aybce7vj60t3zs5ux1i.png)
Finally we have the equation of a line:
![y=(2)/(3)x+1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5ot5mqaglph09hp9zwxzbsk3pkpkf4algf.png)