Question

A car is driven 110 km west and then 40 km southwest, how far is the car from the point of origin?

Answer 1

141.147 km

Step-by-step explanation:

`sin45=(BD)/(BC)\\\Rightarrow BD=BCsin45\\\Rightarrow BD=40* sin45\\\Rightarrow BD=28.28\ km`

Now, AE=BD also CD=BD as the angle B and C are equal

So, from Pythagoras theorem

AC² = AE²+(CD+DE)²

`AC=√(AE^2+(CD+DE)^2)\\\Rightarrow AC=√((40* sin45)^2+(110+40* sin45)^2)\\\Rightarrow AC=141.147\ km`

Displacement of the car is 141.147 km