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The force F = (-90, 40) N acts on a mass of 8 kg. At time t = 0 s, the mass is initially at rest. What is the magnitude of the force (in N)? What are the (x,y) components of the acceleration vector (in m/s^2)? What are the (x,y) components of the velocity vector (in m/s) after 1 seconds?

User Bentham
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1 Answer

3 votes

Answer:

Step-by-step explanation:

Given

Force=(-90,40 ) N

i.e.
F_x=-90 N


F_y=40 N

mass of object=8 kg

to get x component of acceleration


a_x=(-90)/(8)=-11.25 m/s^2


a_y=(40)/(40)=1 m/s^2

Velocity after 1 sec


v_x=u_x+a_xt


v_x=0-11.25* 1=-11.25 m/s


v_y=u_y+a_yt


v_y=0+1* 1=1 m/s

User Mayur Gupta
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