Question

A spring loaded gun shoots a 0.1 kg bullet vertically downward with an initial speed of 16 m/s. How far is the bullet from the muzzle 0.3 s after firing? A) 5.24m below the muzzle

B) 5.24m above the muzzle
C) 0.441m below the muzzle
D) 4.36 m below the muzzle

Answer 1

(a) 5.24 m bellow the muzzle

Step-by-step explanation:

We have given that initial velocity of the bullet u = 16 m/sec

Acceleration due to gravity
`g=9.8m/sec^2`

Time t = 0.3 sec

We have to find the height

According to second equation of motion

`h=ut+(1)/(2)gt^2`

`h=16* 0.3+(1)/(2)* 9.8* 0.3^2=5.241m`

As the bullet is shoots downward so distance will be billow the muzzle

So option (a) will be correct option

Answer 2

The distance of the bullet is 5.24 m below the muzzle.

(A) is correct option.

Step-by-step explanation:

Given that,

Mass of bullet = 0.1 kg

Initial speed = 16 m/s

Time = 0.3 s

We need to calculate the distance

Using equation of motion

`s=ut+(1)/(2)gt^2`

Where, u = initial speed

g = acceleration due to gravity

t = time

Put the value into the formula

`s=16*0.3+(1)/(2)*9.8*(0.3)^2`

`s=5.24\ m`

Hence, The distance of the bullet is 5.24 m below the muzzle.