Question

A gold coin has a mass of 9.25 grams. What is its volume if the density of gold is 19300 kg/m^3?

Answer 1

Volume of gold coin will be
`4.792* 10^(-7)m^3`

Step-by-step explanation:

We have given mass of the gold coin m = 9.25 gram =
`9.25* 10^(-3)kg`

Density of gold is given as d =
`=19300kg/m^3`

We know that density
`=(mass)/(volume)`

So volume
`=(mass)/(density)=(9.25* 10^(-3))/(19300)=4.792* 10^(-7)m^3`

So volume of gold coin will be
`4.792* 10^(-7)m^3`