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What is the escape speed of an electron launched from the surface of a 1.1-cm-diameter glass sphere that has been charged to 9.0 nC ? STEP BY STEP,

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Answer:


v=7.18* 10^7\ m/s

Step-by-step explanation:

Diameter of the glass sphere, d = 1.1 cm = 0.011 m

Charge on the glass sphere,
q=9\ nC=9* 10^(-9)\ C

Let v is the escape speed of the electron that is launched from the surface. Firstly, calculating the electric potential of the sphere as :


V=(kq)/(r)


V=(9* 10^9* 9* 10^(-9))/(0.011/2)

V = 14727.27 volts

The potential energy of the electron cane be calculated as :


U=q* V


U=1.6* 10^(-19)* 14727.27


U=2.35* 10^(-15)\ J

Using conservation of energy to find the speed of the electron as :


U=(1)/(2)mv^2


v=\sqrt{(2U)/(m)}


v=\sqrt{(2* 2.35* 10^(-15))/(9.1* 10^(-31))}


v=7.18* 10^7\ m/s

So, the escape speed of an electron launched from the surface is
7.18* 10^7\ m/s. Hence, this is the required solution.

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