Apples are stored in a container (width = length = 3.5 ft) that is filled to a depth of 2.75 feet. If the unit density of an apple is 49.3 lb/ft^3 and porosity is 31%, how many …

Question

asked Oct 2, 2020 147k views

1 Answer

Lassej · Answer 1 · 2020-10-07T12:39:27+0000

Answer:

The mass of the apples in the box are 1145.95 lb.

Step-by-step explanation:

Given that,

Width = 3.5 ft

length = 3.5 ft

Depth = 2.75 feet

Density = 49.3 lb/ft³

We need to calculate the volume

Using formula of volume

V=l* h* b

Put the value

V=3.5*3.5*2.75

$V=33.6875\ ft^3$

We need to calculate the mass

Using formula of density

$\rho=\dfraxc{m}{V}$

$m=\rho*V$

Put the value into the formula

m=49.3*33.6875

$m=1660.79\ lb$

But porosity is 31 % so apples is 69% mass of total container.

So, Total mass in pounds is

M=(69)/(100)*1660.79

$M=1145.95\ lb$

Hence, The mass of the apples in the box are 1145.95 lb.