Question

Performing Young's double slit experiment using a typical laser pointer with 650 nm wavelength pro duces the first-order maximum at an angle of 32 degrees. At what angle will the first-order maximum occur when repeating the experiment with a laser from a Blueray player, which has a wavelength of 405 nm?

Answer 1

Answer:
`\theta =19.27^(\circ)`

Step-by-step explanation:

Given

wavelength of source=650 nm

angle of bright fringe
`=32^(\circ)`

let d be the distance between slits

`\sin \theta _(bright)=(m\lambda )/(d)`

`\sin32=(1* 650)/(d)`------1

For \lambda =405 nm

`sin\theta =(1* 405)/(d)`------2

Divide 1 & 2

`(sin32)/(sin\theta )=(650)/(405)`

`\theta =19.27^(\circ)`