Question

A force of 8.0 N is along x direction, another force of 6.0 N is along +y direction. If both forces are acting on a point object located at the origin, what is their resultant force on the object?

Answer 1

Resultant force, R = 10 N

Step-by-step explanation:

It is given that,

Force acting along +x direction,
`F_x=8\ N`

Force acting along +y direction,
`F_y=6\ N`

Both the forces are acting on a point object located at the origin. Let the resultant force of the object is given by R. So,

`R=√(F_x^2+F_y^2+F_xF_y\ cos\theta)`

Here
`\theta=90^(\circ)`

`R=√(F_x^2+F_y^2)`

`R=√(8^2+6^2)`

R = 10 N

So, the resultant force on the object is 10 N. Hence, this is the required solution.