Question

hree boxes rest side-by-side on a smooth, horizontal floor. Their masses are 5.0 kg, 3.0 kg, and 2.0 kg, with the 3.0-kg mass in the center. A force of 50 N pushes on the 5.0-kg box, which pushes against the other two boxes. What magnitude force does the 5.0-kg box exert on the 3.0-kg box?

Answer 1

25 N

Step-by-step explanation:

We are given that three boxes rest side-by-side on a smooth, horizontal floor.

`m_1=5 kg`

`m_2= 3 kg`

`m_3=2 kg`

Force applied on 5 kg box=50 N

We have to find the magnitude force exert on the 3 kg box by 5 kg box.

According to given question

`50=(5+3+2)a`

`a=(50)/(10)=5 m/s^2`

When 5 kg box exert force on 3 kg box then equal and opposite force exert on 5 kg box due to 3 kg box and 2 kg box.

Let F be the force exert by 5 kg box on 3 kg box and

`50-F=5\cdot 5`

`F=50-25=25 N`

Hence, the magnitude force exert on 3 kg box by 5 kg box=25 N