Answer:
K.E = 463.04 k J
P = 23.14 Watt
Step-by-step explanation:
given,
mass of automobile = 1200 kg
velocity = 50 km/h
= 50 × 0.278
= 13.9 m/s
kinetic energy =
![(1)/(2)mv^2](https://img.qammunity.org/2020/formulas/physics/college/c5b6sjo75qgp1lhd1c0j9tb988g1thuhej.png)
=
![(1)/(2)* 1200 * 13.9^2](https://img.qammunity.org/2020/formulas/physics/college/lngz4wz9rtk72kcnjzl8mkrjgj9y4g9zo9.png)
K.E = 115.93 k J
vehicle accelerated to velocity = 100 km/h
= 100 × 0.2778
= 27.78 m/s
kinetic energy =
![(1)/(2)mv^2](https://img.qammunity.org/2020/formulas/physics/college/c5b6sjo75qgp1lhd1c0j9tb988g1thuhej.png)
=
![(1)/(2)* 1200 * 27.78^2](https://img.qammunity.org/2020/formulas/physics/college/vo09mlfxp8n73fk5am9g51ymv7grk43kh0.png)
K.E = 463.04 k J
work done = change in kinetic energy
= 463.04 - 115.93
= 347.11 J
Power =
![(work\ done)/(time)](https://img.qammunity.org/2020/formulas/physics/college/3c3jmz624kqchyu0hggat0b8rj6wijkgcf.png)
Power =
![(347.11)/(15)](https://img.qammunity.org/2020/formulas/physics/college/ncu5d3mqolrgde1v692p7gq52w5o7rdf70.png)
P = 23.14 Watt