Question

For a parallel plate capacitor, given: Area of one plate = 41 cm2. Space between the plates = 2.5 mm. Material between the plates = air. Calculate the capacitance. Write your answer in pF (i.e. 10^-12 F)

Answer 1

Capacitance, C = 14.51 F

Step-by-step explanation:

It is given that,

Area of a parallel plate capacitor,
`A=40\ cm^2=0.0041\ m^2`

Spacing between the plates, d = 2.5 mm = 0.0025 m

We need to find the capacitance of the parallel plate capacitor. Its formula is given by :

`C=(A\epsilon_o)/(d)`

`C=(0.0041* 8.85* 10^(-12))/(0.0025)`

`C=1.451* 10^(-11)\ F`

`C=14.51* 10^(-12)\ F`

`C=14.51\ pF`

So, the capacitance of the capacitor is 14.51 pF. Hence, this is the required solution.