Question

A car moving in a straight line starts at x = 0 at t = 0 . It passes the point x = 30.0 m with a speed of 10.0 m/s at t = 3.00 s . It passes the point x = 375 m with a speed of 50.0 m/s at t = 20.0 s . Find the average velocity between t = 3.00 s and t = 20.0 s . Express your answer with the appropriate units.

Find the average acceleration between t = 3.00 s and t = 20.0 s .
Express your answer with the appropriate units.

Answer 1

a)
`v=20.3m/s`

b)
`a=2.35m/s^2`

Step-by-step explanation:

From the exercise we know:

`x_(1)=30m`;
`v_(1)=10m/s`;
`t_(1)=3s`

`x_(2)=375m`;
`v_(2)=50m/s`;
`t_(2)=20s`

The formula for average velocity is:

`v=(x_(2)-x_(1))/(t_(2)-t_(1))`

a)
`v=(375m-30m)/(20s-3s)=20.3m/s`

The formula for average acceleration is:

`a=(v_(2)-v_(1))/(t_(2)-t_(1))`

b)
`a=((50-10)m/s)/((20-3)s)=2.35m/s^2`