Question

A car at rest accelerates at 6.50 m/s2 for 3.00 s. How far does the car travel in this time?

Answer 1

The distance traveled by the car is 29.25 meters

Step-by-step explanation:

The distance traveled by the car can be determine by means of the equations for a Uniformly Accelerated Rectilinear Motion:

`d = v_(0)t + (1)/(2)at^(2)` (1)

Where
`v_(0) = 0` is the initial velocity, a is the acceleration and t is the time.

Since the car starts from rest, its initial velocity will be zero (
`v_(0) = 0`):

`d = (1)/(2)(6.50 m/s^(2))(3.00 s)^(2)`

`d = 29.25 m`

So the distance traveled by the car is 29.25 meters.