Question

A ball is thrown directly upward with a speed of 5.00 m/s. How long does the ball stay in the air until it is caught again at the same height?

Answer 1

Step-by-step explanation:

It is given that,

Speed of the ball, u = 5 m/s

When the ball reaches the same height as that of its initial height, the vertical displacement is equal to zero i.e.
`s_y=0`

Let t is the time for which the ball stay in the air until it caught again at the same height. Using second equation of motion as :

`s_y=ut+(1)/(2)at^2`

Here, a = -g

`ut-(1)/(2)gt^2=0`

`5t-(1)/(2)* 9.8t^2=0`

On solving the above quadratic equation, we get the value of t as :

t = 1.02 seconds

So, the ball stay in the air for 1.02 seconds. Hence, this is the required solution.