Question

A water balloon is thrown at an angle of 30° with a velocity of 40 m/s. How long do you have to move out of the way if the balloon was 20m away from you when it was thrown?

Answer 1

t=0.58s

Step-by-step explanation:

We can consider only the horizontal component since the horizontal component of the velocity is constant (
`v_x=vcos\theta`), and we want to know how much time it takes for the balloon to travel a horizontal distance
`d_x` at that speed. The definition of (horizontal) velocity is
`v_x=(d_x)/(t)`, so we have:

`t=(d_x)/(v_x)=(d_x)/(vcos\theta)=((20m))/((40m/s)cos(30^(\circ)))=0.58s`