Answer:
+5.20 µC
Step-by-step explanation:
Given that
Charge =−5.20 µC and radius= 5.40 cm.
Insert a +10.4- µC charge at the center of the sphere
As we know that according to Gauss's theorem electric field inside the metal is zero.
When +10.4 µC charge insert but the total charge on the sphere should be −5.20 µC.So the charge on the outer surface of the sphere will be +5.20 µC.