Question

The field from a large plate A is 1180 N/C pointing eastward, while another plate B produces a field that is 1520 N/C northward. What is the net field produced by the combination?

?N/C
An object has been charged to 480 μC and placed in the field.
What is the magnitude of the force on the object?
? N

Answer 1

E=1924.26 N/C

F=0.92 N

Step-by-step explanation:

As we know that electric field is a vector quantity.It means that it have direction.

Plate A

E(A) = 1180 N/C ,Eastward

Plate B

E(B) =1520 N/C ,Northward

The resultant electric field given as

`E=√(E_A^2+E_B^2)\ N/C`

`E=√(1180^2+1520^2)\ N/C`

E=1924.26 N/C

We know that

F = q E

Here q =480 μC

E=1924.26 N/C

By putting the values

F = q E

`F=480* 10^(-6)* 1924.26\ N`

F=0.92 N