Question

A jet lands on an aircraft carrier with an initial velocity of 72 m/s. What is its acceleration if it comes to a stop in 10 seconds?

Answer 1

`a=-7.2m/s^2`

Step-by-step explanation:

The definition of acceleration is the change of velocity in time

`a=(v_(2)-v_(1))/(t_(2)-t_(1))`

So, the acceleration of the jet is:

`a=((0-72)m/s)/(10s)=-7.2m/s^2`