235k views
2 votes
Write an equation of a line containing (2, -3) and perpendicular to 3x + 4y = 14.

1 Answer

4 votes

To solve this, we first have to find out what the slope of 3x + 4y = 14

To do this, we solve for y, and use the equation y = mx + b (m = slope)

3x + 4y = 14

4y = - 3x + 14

y = -3/4x + 14/4

So -3/4 is the slope of the line.

But! We need to use the perpendicular version of this slope, which is 4/3

So now we use 4/3 in y = mx + b to find b

-3 = 4/3 (2) + b

-3 = 8/3 + b

-8/3 - 9/3 = b

-17/3 = b

So our final equation is:

y = 4/3x - 17/3

User Robert Haas
by
7.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories