Question

What is the % error in using g = 10.0 m/s^2? (Take the value ofg as 9.8 m/s^2)

Answer 1

So percentage error will be 2 %

Step-by-step explanation:

We have given initial value of acceleration due to gravity
`g=10m/sec^2`

And final value of acceleration due to gravity
`g=9.8m/sec^2`

We have to find the percentage error

We know that percentage error is given by
`percentage\ error=(initial\ value-final\ value)/(initial\ value)* 100`

So
`percentage\ error=(10-9.8)/(10)* 100=2` %