Question

A golf cart is moving at 10 m/s and begins slowly decelerating until it comes to a complete stop after 20 s. what is the average velocity?

what is the displacement?

Answer 1

`v_(avg) = 5\ m/s`

displacement = 100 m

Step-by-step explanation:

given,

initial velocity of cart = 10 m/s

golf cart is slowly decelerating

time taken to stop = 20 s

final velocity = 0 m/s

using equation of motion

v = u + a t

0 = 10 - a× 20

a = 0.5 m/s²

`Average\ velocity = (total\ displacement)/(total\ time)`

total displacement

v² = u² + 2 a s

0 = 10² - 2 × 0.5 ×s

s = 100 m

now,

`Average\ velocity = (total\ displacement)/(total\ time)`

`v_(avg) = (100)/(20)`

`v_(avg) = 5\ m/s`