Question

A block slides on a frictionless surface. The block is given a 25 N force to the right and it accelerates at a rate of 3.5 m/s^2 to the right. This block is then placed on a frictionless surface on Jupiter and given a force of 15 N. What is the acceleration on the block? (1 point)

1.7 m/s^2
8.9 m/s^2
4.3 m/s^2
2.1 m/s^2

Answer 1

2.1 m/s^2

Step-by-step explanation:

Answer 2

Answer: The acceleration of the block is
`2.10m/s^2`

Step-by-step explanation:

Force is defined as the push or pull on an object with some mass that causes change in its velocity.

It is also defined as the mass multiplied by the acceleration of the object.

Mathematically,

`F=m* a` .......(1)

where,

F = force exerted on the block = 25 N

m = mass of the block = ?

a = acceleration of the block =
`3.5m/s^2`

Putting values in equation 1, we get:

`25kg.m/s^2=m* 3.5m/s^2\\\\m=(25)/(3.5)=7.14kg`

As, the mass of the block remains the same everywhere in the universe.

Now, calculating the acceleration on the block on Jupiter by using equation 1:

Force on the block = 15 N

Mass of the block = 7.14 kg

Putting values in equation 1, we get:

`15kg.m/s^2=7.14kg* a\\\\a=(15)/(7.14)=2.10m/s^2`

Hence, the acceleration of the block is
`2.10m/s^2`