Question

A force vector has a magnitude of 579 newtons and points at an angle 38.0° of below the positive x axis. (a) What is the the x scalar component of the vector?

Fx = _____ N

(b) What is the y scalar component of the vector?
Fy = ______ N

Answer 1

a) x- component of force = 432.62 N

b)y- component of force = 338 N

Step-by-step explanation:

given,

magnitude of force = 549 N

angle between the force vector with positive horizontal x-axis(∅) = 38.0°

a) x-scalar component of the force vector

x- component of force = F cos ∅

x- component of force = 549 cos 38°

x- component of force = 432.62 N

b) y-scalar component of the force vector

y- component of force = F sin ∅

y- component of force = 549 sin 38°

y- component of force = 338 N