Question

What were the dimensions of the original photo?

Miriam reduced a square photo by cutting 3 inches away
from the length and the width so it will fit in her photo album.
The area of the reduced photo is 64 square inches. In the
equation (x-3) = 64, X represents the side measure of the
original photo.
11 inches by 11 inches
5 inches by 5 inches
O
3 + 4/2 inches by 3 + 4/2 inches
O 3 - 42 inches by 3 - 42 inches

Answer 1

Answer is 11 by 11 Which is A

Explanation:

I just guessed and got it right

Answer 2

A. 11 inches by 11 inches

Explanation:

We have been given an equation
`(x-3)^2=64`, where x represents the side measure of the original photo. The equation represents the area the area of the reduced photo. We are asked to find the dimensions of the original photo.

Let us solve for x by taking positive square root of both sides.

`√((x-3)^2)=√(64)`

`√((x-3)^2)=√(8^2)`

`x-3=8`

Add 3 on both sides:

`x-3+3=8+3`

`x=11`

Therefore, the dimensions of the original photo are 11 inches by 11 inches and option A is the correct choice.