Answer:
The probability that the dogs are blue eyed and deaf is 13.02%.
Explanation:
We are given the following information in the question:
P(Blue eyes) = 31%
P(Deaf) = 38%
P(Deaf | Blue eyes) = 42%
Formula for conditional probability:
![P( A|B) = \displaystyle(P(A \cap B))/(P(B))](https://img.qammunity.org/2020/formulas/mathematics/high-school/mlo381q1cazbaavmo8usqa8thynkta5uzl.png)
Now, let A be the event where the dog is deaf and B be the the event where dog is blue eyed.
![P( \text{ Deaf}|\text{Blue eyes}) = \displaystyle\frac{P( \text{Deaf} \cap \text{Blue eyes})}{P(\text{Blue eyes})}\\\\0.42 = \displaystyle\frac{P( \text{Deaf} \cap \text{Blue eyes})}{0.31}\\\\P( \text{Deaf} \cap \text{Blue eyes}) = 0.42* 0.31 = 0.1302 = 13.02\%](https://img.qammunity.org/2020/formulas/mathematics/high-school/haz5th9l94zcxznl9d2cjv4kyskn0yxp03.png)
Hence, the probability that the dogs are blue eyed and deaf is 13.02%.