Question

Solve for x in the equation x^2-10x+25=35.

Answer 1

`x = (10)/(2)` ±
`(√(60))/(2)`

Explanation:

`x^(2) - 10x + 25 = 35`

`x^(2) -10x - 10` Subtract 35 from both sides to make the equation equal to zero

Quadratic equation is needed to solve this

`\frac{-b ± \sqrt{b^(2)-4(a)(c)}}{2a}`

`ax^(2) + bx + c`

a = 1

b = -10

c = -10

`\frac{-(-10) ± \sqrt{(-10)^(2)-4(1)(-10)}}{2(1)}`

`(10 ± √(100-4(-10)))/(2)`

`(10 ± √(100-(-40)))/(2)`

`(10 ± √(100 + 40))/(2)`

`(10 ± √(60))/(2)`

`x = (10)/(2)`±
`(√(60))/(2)`