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A forklift raises a crate weighing 8.35 × 102 newtons to a height of 6.0 meters. What amount of work does the forklift do? A. 2.5 × 103 joules B. 5.0 × 103 joules C. 2.4 × 104 joules D. 4.9 × 104 joules

2 Answers

7 votes

Answer:

B. 5.0 × 103 joules

Step-by-step explanation:

just took the test

User Erikbstack
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1 vote

Answer:

B.
5.0*10^3 J

Step-by-step explanation:

The work done by the forklift equals the force that it exerts on the object to move it (equal in magnitude to the weight of the crate), times the vertical distance it was moved.


W=8.35*10^2 N * 6 m= 50.1 *10^2=5.01*10^3J

where we have written the final numerical value using scientific notation, and given the work the units of Joules (J) due to the fact that all involved quantities were shown in appropriate SI units. We can round our answer to only one decimal, in order to match the answer shown in the list of options.

User Sterling Diaz
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5.0k points