Answer:
7 hours
Step-by-step explanation:
The total charge contained in the battery is
![Q = 49 A \cdot h](https://img.qammunity.org/2020/formulas/physics/high-school/7ld8w9e6yqlpu8o44d9w46l25krpirdtsu.png)
And this is a charge, since it is a current multiplied by a time:
![Q=It](https://img.qammunity.org/2020/formulas/physics/college/y57gjxa7ykv0gqs2ng733kv4r1bvdnu0qe.png)
The current drawn by each headlight (which is the charge consumed per second) is
![I=3.5 A](https://img.qammunity.org/2020/formulas/physics/high-school/xdc10upesuzfs53bc1sqjo05q0bzbinwnk.png)
Since we have two headlight, the total current drawn is
![I=3.5 \cdot 2 = 7 A](https://img.qammunity.org/2020/formulas/physics/high-school/6raq2uiroe104l14rt9cutiaik3tc6ojc7.png)
Therefore, the total charge consumed by the two headlights each hour is
![q = I \cdot h = 7 A \cdot h](https://img.qammunity.org/2020/formulas/physics/high-school/xb0jzbquu8oviy9eebrpj2oo0gnmho31bw.png)
So, the time before the battery is dead is
![t=(Q)/(q)=(49 Ah)/(7Ah)=7 h](https://img.qammunity.org/2020/formulas/physics/high-school/golh2b9i3a2gu6psaappth6mvjisrc72pi.png)