Question

A shell is fired from the ground with an initial speed of 1.57 ✕ 103 m/s at an initial angle of 38° to the horizontal. (a) Neglecting air resistance, find the shell's horizontal range. 122000 Incorrect: Your answer is incorrect. m (b) Find the amount of time the shell is in motion. 98.6 Incorrect: Your answer is incorrect. s

Answer 1

a) Shell's horizontal range = 243798.70 m

b) The amount of time the shell is in motion = 197.06 s

Step-by-step explanation:

Consider the vertical motion of projectile,

We have equation of motion s = ut + 0.5 at²

Initial velocity, u = 1.57 x 10³ sin 38 = 966.59 m/s

Acceleration, a = -9.81 m/s²

Displacement is zero when the shell reaches back to ground, s = 0 m

Time, t =?

Substituting,

s = ut + 0.5 at²

0 = 966.59 x t + 0.5 x (-9.81) x t²

t = 197.06 seconds

b) The amount of time the shell is in motion = 197.06 s

a) Consider the horizontal motion of shell

We have equation of motion s = ut + 0.5 at²

Initial velocity, u = 1.57 x 10³ cos 38 = 1237.18 m/s

Acceleration, a = 0 m/s²

Displacement, s = ?

Time, t = 197.06 s

Substituting,

s = ut + 0.5 at²

s = 1237.18 x 197.06 + 0.5 x 0 x 197.06²

s =243798.70 m

Shell's horizontal range = 243798.70 m