Answer:
Step-by-step explanation:
You must mean how to solve. I'll solve the equation for you.
Step-by-step explanation:
√
2
x
+
3
−
√
x
+
1
=
1
√
2
x
+
3
=
1
+
√
x
+
1
(
√
2
x
+
3
)
2
=
(
1
+
√
x
+
1
)
2
2
x
+
3
=
1
+
2
√
x
+
1
+
x
+
1
2
x
−
x
+
3
−
1
−
1
=
2
√
x
+
1
x
+
1
=
2
√
x
+
1
(
x
+
1
)
2
=
(
2
√
x
+
1
)
2
x
2
+
2
x
+
1
=
4
(
x
+
1
)
x
2
+
2
x
+
1
=
4
x
+
4
x
2
+
2
x
−
4
x
+
1
−
4
=
0
x
2
−
2
x
−
3
=
0
(
x
−
3
)
(
x
+
1
)
=
0
x
=
3
and
x
=
−
1
Always check the solutions in the original equation to make sure they aren't extraneous. If they do not work in the original equation, you must reject them.
√
2
×
3
+
3
−
√
3
+
1
=
1
So, x = 3 works. Now, let's check x = -1:
√
2
×
−
1
+
3
−
√
−
1
+
1
=
1
So, x = -1 works as well.
Your solution set would be x = 3, -1
Practice exercises:
Solve for x.
a)
√
3
x
−
2
−
√
x
−
2
=
2
b)
√
4
x
+
5
+
√
8
x
+
9
=
12
Related questions
How do you solve radical You must mean how to solve. I'll solve the equation for you.
Step-by-step explanation:
√
2
x
+
3
−
√
x
+
1
=
1
√
2
x
+
3
=
1
+
√
x
+
1
(
√
2
x
+
3
)
2
=
(
1
+
√
x
+
1
)
2
2
x
+
3
=
1
+
2
√
x
+
1
+
x
+
1
2
x
−
x
+
3
−
1
−
1
=
2
√
x
+
1
x
+
1
=
2
√
x
+
1
(
x
+
1
)
2
=
(
2
√
x
+
1
)
2
x
2
+
2
x
+
1
=
4
(
x
+
1
)
x
2
+
2
x
+
1
=
4
x
+
4
x
2
+
2
x
−
4
x
+
1
−
4
=
0
x
2
−
2
x
−
3
=
0
(
x
−
3
)
(
x
+
1
)
=
0
x
=
3
and
x
=
−
1
Always check the solutions in the original equation to make sure they aren't extraneous. If they do not work in the original equation, you must reject them.
√
2
×
3
+
3
−
√
3
+
1
=
1
So, x = 3 works. Now, let's check x = -1:
√
2
×
−
1
+
3
−
√
−
1
+
1
=
1
So, x = -1 works as well.
Your solution set would be x = 3, -1
Practice exercises:
Solve for x.
a)
√
3
x
−
2
−
√
x
−
2
=
2
b)
√
4
x
+
5
+
√
8
x
+
9
=
12
Related questions
How do you solve radical