Question

In the simple Bohr model of the eighth excited state of the hydrogen atom, the electron travels in a circular orbit around a fixed proton. The radius of the orbit is 4.28 ✕ 10−9 m, and the speed of the electron is 2.43 ✕ 105 m/s. The mass of an electron is 9.11 ✕ 10−31 kg. What is the force on the electron (in N)? (Enter the magnitude.)

Answer 1

Net force on electron will be
`12.568* 10^(-12)N`

Step-by-step explanation:

We have given that the orbit
`r=4.28* 10^(-9)m`

Speed of the electron
`v=2.43* 10^5m/sec`

Mass of the electron is given as
`m=9.11* 10^(-31)kg`

Centripetal acceleration is given by
`a_c=(v^2)/(r)=((2.43* 10^5)^2)/(4.28* 10^(-9))=1.3796* 10^(19)m/sec^2`

Force is given by F = ma

So force
`F=9.11* 10^(-31)* 1.3796* 10^(19)=12.568* 10^(-12)N`